document.write( "Question 986704: A ladder 5m long leans against a vertical wall with an angle of 70 to the ground. The ladder slips down the wall 2m down the ground. Find
\n" ); document.write( "(a) the new angle which the ladder makes on the ground
\n" ); document.write( "(b)the distance the ladder has sliped back on the ground from its original position
\n" ); document.write( "THANK YOU
\n" ); document.write( "

Algebra.Com's Answer #607497 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Find the original position of the ladder.
\n" ); document.write( "Distance from wall to ladder : \"d%5Bx%5D=5cos%2870%29=1.710\"\"m\"
\n" ); document.write( "Distance from floor to ladder : \"d%5By%5D=5sin%2870%29=4.698\"\"m\"
\n" ); document.write( "So the new position is,
\n" ); document.write( "\"d%5By%5D=4.698-2=2.698\"
\n" ); document.write( "\"5sin%28theta%29=2.698\"
\n" ); document.write( "\"sin%28theta%29=0.53969\"
\n" ); document.write( "\"theta=32.7\"
\n" ); document.write( "The new position from the wall is,
\n" ); document.write( "\"d%5Bx%5D=5cos%2832.7%29=4.209\"\"m\"
\n" ); document.write( "So the difference in x position is,
\n" ); document.write( "\"DELTA=4.209-1.710\"
\n" ); document.write( "\"DELTA=2.499\"\"m\"
\n" ); document.write( "or \"2.5\"\"m\"
\n" ); document.write( "
\n" ); document.write( "
\n" );