document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986685>Question 986685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the gradient of the tangent to the following curve at the point where x=2\r<BR>\n" );
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document.write( "y=2x^1/2 - 2/x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607460 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "y = 2x^1/2 - 2/x<BR>\n" );
document.write( "y = 2x^1/2 - 2x^-1<BR>\n" );
document.write( "Differentiate:<BR>\n" );
document.write( "dy/dx = x^-1/2 + 2x^-2<BR>\n" );
document.write( "dy/dx = 1/x^1/2 + 2/x^2<BR>\n" );
document.write( "Substitute x = 2<BR>\n" );
document.write( "=1/sqrt2 + 2/(2)^2<BR>\n" );
document.write( "= 1/sqrt2 + 2/4<BR>\n" );
document.write( "= 1/sqrt2 + 1/2<BR>\n" );
document.write( "= 1.2<BR>\n" );
document.write( "The gradient = 1.2<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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