document.write( "Question 986605: Mike and Adam left a bus terminal at the same time and traveled in opposite directions. Mikes bus was in heavy traffic and had to travel 20 mi/h slower than Adams bus. After 3 hours, their buses were 270 miles apart. How fast was each bus going
\n" ); document.write( "Now my question is how do I set up the equation to be able to solve it
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Algebra.Com's Answer #607456 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+s+\" = the speed of Adam's bus
\n" ); document.write( "\"+s+-+20+\" = the speed of Mike's bus
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\n" ); document.write( "The best way to solve this is to think of one
\n" ); document.write( "of the buses standing still and the other one
\n" ); document.write( "traveling at the sum of their speeds.
\n" ); document.write( "It doesn't matter which one is standing still
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\n" ); document.write( "\"+270+=+%28+s+%2B+s+-+20+%29%2A3+\"
\n" ); document.write( "\"+270+=+%28+2s+-+20+%29%2A3+\"
\n" ); document.write( "\"+270+=+6s+-+60+\"
\n" ); document.write( "\"+6s+=+330+\"
\n" ); document.write( "\"+s+=+55+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+-+20+=+35+\"
\n" ); document.write( "The speed of Adam's bus is 55 mi/hr
\n" ); document.write( "The speed of Mike's bus is 35 mi/hr
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\n" ); document.write( "check:
\n" ); document.write( "\"+d%5B1%5D+=+55%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+165+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+35%2A3+\"
\n" ); document.write( "\"+d%5B2%5D+=+105+\" mi
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\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+165+%2B+105+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+270+\" mi
\n" ); document.write( "OK
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