document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986584>Question 986584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm stumped on a question concerning arithmetic and geometric recursive formulas. I am given four terms, and I'm asked to write the common ratio, and to find the tenth term. \r<BR>\n" );
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document.write( "The first four terms given are: 15000, 4500, 1350, 405, 121.5  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607446 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52782)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "4500 = 15000*0.3;\r<BR>\n" );
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document.write( "1350 = 4500*0.3;\r<BR>\n" );
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document.write( "405 = 1350*0.3;\r<BR>\n" );
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document.write( "121.5 = 405*0.3.\r<BR>\n" );
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document.write( "The given &nbsp;5&nbsp; numbers are the first &nbsp;5&nbsp; terms of a geometric progression with the first term &nbsp;15000&nbsp; and the common ratio &nbsp;0.3.\r<BR>\n" );
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document.write( "Therefore, &nbsp;you may expect that the next term is &nbsp;121.5*0.3 = 36.45.\r<BR>\n" );
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