document.write( "Question 986411: Two cars are moving at constant velocity to the right. Initially (at time t=0) car A is 6.0 miles ahead of car B. Car A has a velocity of 35.4 mph and car B has a velocity of 24.8 mph.
\n" ); document.write( "If at some point car B catches up with car A, answer when this will happen (in minutes).
\n" ); document.write( "If car B never catches up with car B, answer how far (in miles) the cars are from each other after 10.3 minutes of driving. \n" ); document.write( "
Algebra.Com's Answer #607351 by ankor@dixie-net.com(22740)\"\" \"About 
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Two cars are moving at constant velocity to the right.
\n" ); document.write( " Initially (at time t=0) car A is 6.0 miles ahead of car B.
\n" ); document.write( " Car A has a velocity of 35.4 mph and car B has a velocity of 24.8 mph.
\n" ); document.write( ":
\n" ); document.write( "If at some point car B catches up with car A, answer when this will happen (in minutes).
\n" ); document.write( "Since Car A (which is ahead of B) is going faster than B, this will never happen
\n" ); document.write( ":
\n" ); document.write( "If car B never catches up with car B, answer how far (in miles) the cars are from each other after 10.3 minutes of driving.
\n" ); document.write( ":
\n" ); document.write( "let d = their distance apart after 10.3 min
\n" ); document.write( "We are using mph here so change 10.3 min to hrs
\n" ); document.write( "10.3/60 = .1717 hrs
\n" ); document.write( "d = .1717(35.4-24.8) + 6
\n" ); document.write( "d = .1717(10.6) + 6
\n" ); document.write( "d = 1.82 + 6
\n" ); document.write( "d = 7.82 mi apart after 10.3 min\r
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