document.write( "Question 986562: A mixture contains alcohol and water in the ratio of 12:5. On adding 14litres of water, the ratio of alcohol to water becomes 4:3. The quantity of alcohol in the mixture is? \n" ); document.write( "
Algebra.Com's Answer #607338 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
alcohol:water
\n" ); document.write( "12:5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Fourteen liters of water added, making 4:3.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Initial blend is \"5%2F%2812%2B5%29=5%2F17\" in water.
\n" ); document.write( "New blend becomes \"3%2F7\" in water. Also \"4%2F7\" in alcohol.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "h, how much initial alcohol
\n" ); document.write( "w, how much initial water
\n" ); document.write( "Ration initially h:w
\n" ); document.write( "\"h%2Fw=12%2F5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "New fraction blend as alcohol, \"4%2F7\";
\n" ); document.write( "\"h%2812%2F17%29%2F%28h%2Bw%2B14%29=4%2F7\"
\n" ); document.write( "The water adds to the amount of blend, but does not add to the fraction of alcohol.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use the initial ratio solved for w, and substitute into the new blend alcohol equation.
\n" ); document.write( "\"w%2Fh=5%2F12\"
\n" ); document.write( "\"w=h%285%2F12%29\"
\n" ); document.write( "-
\n" ); document.write( "\"highlight_green%28h%2812%2F17%29%2F%28h%2B%285%2F12%29h%2B14%29=4%2F7%29\"
\n" ); document.write( "Solve this equation for h.
\n" ); document.write( "
\n" );