document.write( "Question 84334This question is from textbook Prentice Hall Algebra 1 California Edition
\n" ); document.write( ": Square root of x+56=x \n" ); document.write( "
Algebra.Com's Answer #60731 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Square root of x+56=x\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%2B56%29=x\" square both sides to get rid of the radical and we get:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B56=x%5E2\" subtract x and also 56 from both sides\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-56=x-x%2B56-56\" collect like terms\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-56=0\" quadratic in standard form and it can be factored\r
\n" ); document.write( "\n" ); document.write( "\"%28x-8%29%28x%2B7%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x-8=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x=8\" and\r
\n" ); document.write( "\n" ); document.write( "\"x%2B7=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-7\"\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%288%2B56%29=8\"
\n" ); document.write( "\"sqrt%2864%29=8\"
\n" ); document.write( "\"8=8\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28-7%2B56%29=-7\"
\n" ); document.write( "\"sqrt+%2849%29=-7\"
\n" ); document.write( "Since the square root of 49 is plus or minus 7, this solution works also.\r
\n" ); document.write( "\n" ); document.write( "(Note: If the A coefficient of a quadratic is 1, then the B coefficient is the sum of the factors of the C coefficient. In this case, the factors of the C coefficient that work are -8 and +7)\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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