document.write( "Question 84324This question is from textbook Coll. Alg. Graphing Approach
\n" ); document.write( ": 1 over(x+h)^2 minus 1 over x^2 all this over h. I have the solutions manual but I don't now how they got x^2-(x+h)^2 for the numerator after mult. by LCD. What happened to the 1's in the original numerator? Thank you! Jackie \n" ); document.write( "
Algebra.Com's Answer #60727 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"%281+%2F%28%28x%2Bh%29%5E2%29+-+1+%2F%28+x%5E2%29%29+%2Fh\"\r
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\n" ); document.write( "\n" ); document.write( "It may help to write this in a different format:\r
\n" ); document.write( "\n" ); document.write( "\"1+%2F%28%28x%2Bh%29%5E2%29+-+1+%2F%28+x%5E2%29+\" DIVIDED BY \"h\"
\n" ); document.write( "\"%281+%2F%28%28x%2Bh%29%5E2%29+-+1+%2F%28+x%5E2%29%29%2A+%281%2Fh%29\" \r
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\n" ); document.write( "\n" ); document.write( "Now, you have to get the common denominator \"x%5E2%28x%2Bh%29%5E2\" before you can subtract the first two fractions:
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\n" ); document.write( "\n" ); document.write( "It's hairy, but this is why your numerator is \"+1%2Ax%5E2+-+1%2A%28x%2Bh%29%5E2+\", over the common denominator (times h, of course). \r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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