document.write( "Question 986511: Find the dimensions of a right triangle if the area is 48 and one leg is 4 less than twice the other leg. \r
\n" ); document.write( "\n" ); document.write( "my attempt goes this way:\r
\n" ); document.write( "\n" ); document.write( "A=1/2 bh
\n" ); document.write( "48=1/2 (2x-4) (x)
\n" ); document.write( "48=1/2 (2x^2-4x)
\n" ); document.write( "48=x^2-2x
\n" ); document.write( "0=x^2-2x-48
\n" ); document.write( "then i used quadratic formula but i'll only use plus sign here because i don't know how to type in the plus and minus sign.\r
\n" ); document.write( "\n" ); document.write( "----it seems i can't type the equation properly here--but i only substituted the formula from the equation i got in the area part.
\n" ); document.write( "
\n" ); document.write( " here is my theory or the answer i got.\r
\n" ); document.write( "\n" ); document.write( "x=8
\n" ); document.write( "2x-4=12\r
\n" ); document.write( "\n" ); document.write( " i can't seem to get the hypotenuse using these two answers because i get a decimal answer.\r
\n" ); document.write( "\n" ); document.write( "c^2=a^2+b^2 , using the Pythagorean theorem, i got an answer with a decimal, which in my opinion is wrong.
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Algebra.Com's Answer #607267 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"A=%281%2F2%29+bh\"........correct
\n" ); document.write( "\"48=%281%2F2+%29%282x-4%29%28x%29\"........correct
\n" ); document.write( "\"48=%281%2F2%29+%282x%5E2-4x%29\"........correct
\n" ); document.write( "\"48=x%5E2-2x\"........correct
\n" ); document.write( "\"0=x%5E2-2x-48\"........correct\r
\n" ); document.write( "\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "\n" ); document.write( " \"x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A%28-48%29+%29%29%2F%282%2A1%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4%2B192+%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+196+%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+14%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "positive solution:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B+14%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=16%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+8%29+\"=> this is a height\r
\n" ); document.write( "\n" ); document.write( "now find the length of the base
\n" ); document.write( "\"b=2x-4\"
\n" ); document.write( "\"b=2%2A8-4\"
\n" ); document.write( "\"b=16-4\"
\n" ); document.write( "\"highlight%28b=12%29\"=>the base\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "
\n" ); document.write( "\"A=%281%2F2%29+bh\"\r
\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29+8%2A12\"\r
\n" ); document.write( "\n" ); document.write( "\"A=%281%2Fcross%282%291%29cross%28+8%294%2A12\"\r
\n" ); document.write( "\n" ); document.write( "\"A=4%2A12\"\r
\n" ); document.write( "\n" ); document.write( "\"A=48\"\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the hypotenuse:\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=8%5E2%2B12%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=64%2B144+\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=208+\"\r
\n" ); document.write( "\n" ); document.write( "\"c=sqrt%28208%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"c=14.42220510185596+\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28c=14.4%29+\"........must be decimal\r
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