document.write( "Question 986481: Given AC=2(AB)
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Algebra.Com's Answer #607250 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "You can't prove that B is the midpoint of AC. Consider the following situation:\r
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\n" ); document.write( "\n" ); document.write( "The measure of AC is 4 units and the measure of AB is 2 units. 2 times 2 is certainly 4, but B is certainly not the midpoint of AC.\r
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\n" ); document.write( "\n" ); document.write( "Now if you had bothered to mention that B was located on the line segment AC, that would have been a different story. But that isn't what you asked, is it?\r
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\n" ); document.write( "\n" ); document.write( "Extra credit: Why would it have been insufficient to state that A, B, and C are collinear?\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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