document.write( "Question 986481: Given AC=2(AB)
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document.write( "Prove B is the midpoint of AC \n" );
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Algebra.Com's Answer #607250 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can't prove that B is the midpoint of AC. Consider the following situation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The measure of AC is 4 units and the measure of AB is 2 units. 2 times 2 is certainly 4, but B is certainly not the midpoint of AC.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now if you had bothered to mention that B was located on the line segment AC, that would have been a different story. But that isn't what you asked, is it?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Extra credit: Why would it have been insufficient to state that A, B, and C are collinear?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |