document.write( "Question 84318This question is from textbook
\n" ); document.write( ": I am confused as to how to find the radius and center of a circle by using an equation. Here's the equation:
\n" ); document.write( "
\n" ); document.write( "x^-4x+y^+2y=-1
\n" ); document.write( "

Algebra.Com's Answer #60725 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
You must complete the square on the x and y terms respectively:
\n" ); document.write( "\"x%5E2-4x+%2By%5E2%2B2y=-1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You must \"complete the square\" by taking HALF of the x coefficient, and SQUARE the result, adding this amount to each side of the equation. Repeat by taking HALF of the Y coefficient, SQUARE, and add to each side of the equation. It should look like this:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x%2B____%2By%5E2%2B2y%2B____=-1%2B____%2B____\"
\n" ); document.write( "\"x%5E2-4x+%2B+4++%2By%5E2%2B2y%2B1=-1%2B4%2B1\"
\n" ); document.write( "\"+%28x-2%29%5E2+%2B%28y%2B1%29%5E2+=+4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The center is at x=2 and y=-1, and r^2 = 4.
\n" ); document.write( "Therefore, the center is (2,-1) and r=2.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( "
\n" );