document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84273>Question 84273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Graph f(x) = –3x + 2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60723 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = -3x + 2\r<BR>\n" );
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document.write( "The graph is a straight line, with a y-intercept at 2, and the slope is -3.  This means to start with the first point by going UP 2 units on the y-axis.  Then, from this point move DOWN 3, RIGHT 1 unit, and put the second point.  Connect the two points with a straight line, and it should look like this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph+%28300%2C300%2C+-10%2C10%2C-10%2C10%2C+-3x%2B2%29+ ALIGN=MIDDLE  ALT=\"graph+%28300%2C300%2C+-10%2C10%2C-10%2C10%2C+-3x%2B2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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