document.write( "Question 986460: Peter can do a whole job in half the time it takes Henry to do it. Together they can finish the job in 10 days. How many days will it take Peter to do the job alone?
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Algebra.Com's Answer #607209 by josgarithmetic(39621)\"\" \"About 
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document.write( "PERSON   RATE\r\n" );
document.write( "Peter    2/x\r\n" );
document.write( "Henry    1/x\r\n" );
document.write( "Joint    1/10\r\n" );
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\n" ); document.write( "Find Henry's rate first unless you want to take the unknown times from another viewpoint.\r
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\n" ); document.write( "\n" ); document.write( "Note that x is not a rate; it is the time for Henry to do one whole job himself.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Fx%2B1%2Fx=1%2F10\"
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\n" ); document.write( "\"3%2Fx=1%2F10\"
\n" ); document.write( "\"x%2F3=10\"
\n" ); document.write( "\"x=30\"-----time in days for Henry to do one job alone.\r
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\n" ); document.write( "\n" ); document.write( "The practical sense is that Peter is twice as fast as Henry, so Peter can do the same one job alone in 15 days. \n" ); document.write( "
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