document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986440>Question 986440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an automobile engine can run on a mixture of gasoline and a substitute fuel. if gas costs $3.25 per gallon and the substitute fuel costs $2 per gallon, what percent of mixture must be substitute fuel to bring the cost down to $3.00 per gallon? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607192 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> an automobile engine can run on a mixture of gasoline and a substitute fuel. if gas costs $3.25 per gallon and the substitute fuel costs $2 per gallon, what percent of mixture must be substitute fuel to bring the cost down to $3.00 per gallon?<BR>\n" );
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document.write( "Equation for on2 gallon of mixture::<BR>\n" );
document.write( "3.25x + 2(1-x) = 3.00<BR>\n" );
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document.write( "325x + 200 - 200x = 300<BR>\n" );
document.write( "125x = 100<BR>\n" );
document.write( "x = 0.8 gallons (amt of $3.25 gasoline)<BR>\n" );
document.write( "1-x = 0.2 gallons (amt of $2.00 gasoline)<BR>\n" );
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document.write( "Ans: 0.2 = 20% substitute fuel<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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