document.write( "Question 986399: I really need help with this question.
\n" ); document.write( "Find the sum of 34+35+36+37+...+102+103
\n" ); document.write( "I have been trying to figure it out, but now I am just getting frustrated. Please help me step by step on what I am actually supposed to do!
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Algebra.Com's Answer #607168 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
This is an arithmetic sequence with common difference of d = 1. The first term is a = 34\r
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\n" ); document.write( "\n" ); document.write( "Subtract the last term and first term to get: 103-34 = 69. Add on 1 to get 69+1 = 70. So there are 70 terms in the summation above. This means n = 70\r
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\n" ); document.write( "\n" ); document.write( "We have these three values
\n" ); document.write( "a = 34
\n" ); document.write( "d = 1
\n" ); document.write( "n = 70\r
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\n" ); document.write( "\n" ); document.write( "Plug them into the arithmetic sum formula. Doing all that will give you\r
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\n" ); document.write( "\n" ); document.write( "\"S%5Bn%5D+=+%28n%2A%282%2Aa%2Bd%2A%28n-1%29%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"S%5B70%5D+=+%2870%2A%282%2A34%2B1%2A%2870-1%29%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"S%5B70%5D+=+4795\"\r
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\n" ); document.write( "\n" ); document.write( "In the end, 34+35+36+37+...+102+103 = 4,795\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, or if you have any questions about the problem, feel free to email me at jim_thompson5910@hotmail.com
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