document.write( "Question 986277: Please help me sole this. Driving East along the I-10, McKay saw a sign that read: Lonestar, Texas 128 miles, Boring, Texas 202 miles. Then, a second sign showed the distance to Boring was twice the distance to Lonestar. Later a third sign showed that the distance to Boring was three times the distance to Lonestar. How many miles apart were the second and third signs? \n" ); document.write( "
Algebra.Com's Answer #607159 by ankor@dixie-net.com(22740)\"\" \"About 
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Driving East along the I-10, McKay saw a sign that read: Lonestar, Texas 128 miles, Boring, Texas 202 miles.
\n" ); document.write( " Then, a second sign showed the distance to Boring was twice the distance to Lonestar.
\n" ); document.write( " Later a third sign showed that the distance to Boring was three times the distance to Lonestar.
\n" ); document.write( " How many miles apart were the second and third signs?
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\n" ); document.write( "Find the distance from Boring to Lonestar:
\n" ); document.write( "202 - 128 = 74 mi
\n" ); document.write( ":
\n" ); document.write( "The first sign where Boring is Twice the dist to L.S, would be
\n" ); document.write( "Lonestar 74 mi and Boring 148 mi (74 mi between them)
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\n" ); document.write( "The 2nd sign where Boring is three times the dist from L.S:
\n" ); document.write( "let x = dist from L.S.
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\n" ); document.write( "Good question, a screw up on my part is the answer. Will try to correct here
\n" ); document.write( "3x = x + 74
\n" ); document.write( "3x - x = 74
\n" ); document.write( "2x = 74
\n" ); document.write( "x = 37 mi to L.S. and 74+37 = 111 mi to Boring
\n" ); document.write( "Find the distance between the two signs using the distance from L.S.
\n" ); document.write( "74 - 37 = 37 mi between the signs
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\n" ); document.write( "I don't know what happened, I guess I just like 72 better than 74
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