document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986297>Question 986297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this: The largest area of an equilateral triangle which can be formed by a given length of a wire is 484&#8730;3sq.cm.If the same wire is bent twice,first to form a circle and then a square; find the ratio between there area<BR>\n" );
document.write( "Answer: 14:11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607155 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> TRIANGLE\r<BR>\n" );
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document.write( "Find the perimeter, same as the original length of wire.<BR>\n" );
document.write( "a, altitude,<BR>\n" );
document.write( "x, length of one of the equal sides<BR>\n" );
document.write( "Draw the picture.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2B%28x%2F2%29%5E2=x%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2B%28x%2F2%29%5E2=x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "algebra steps<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=%28sqrt%283%29%2F2%29x ALIGN=MIDDLE  ALT=\"a=%28sqrt%283%29%2F2%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Use the given area<BR>\n" );
document.write( "Note that base will be x, height will be a.<BR>\n" );
document.write( "We should use the entire triangle <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29x%2Aa=484sqrt%283%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29x%2Aa=484sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29x%2A%28sqrt%283%29%2F2%29x=484sqrt%283%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29x%2A%28sqrt%283%29%2F2%29x=484sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F4%29x%5E2=484 ALIGN=MIDDLE  ALT=\"%281%2F4%29x%5E2=484\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=4%2A484 ALIGN=MIDDLE  ALT=\"x%5E2=4%2A484\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=sqrt%284%2A4%2A121%29 ALIGN=MIDDLE  ALT=\"x=sqrt%284%2A4%2A121%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=44%29 ALIGN=MIDDLE  ALT=\"highlight%28x=44%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-<BR>\n" );
document.write( "This means that the <b>perimeter of the equilateral triangle</b> is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28132%2Acentimeters%29 ALIGN=MIDDLE  ALT=\"highlight%28132%2Acentimeters%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "SQUARE<BR>\n" );
document.write( "Need side length to find its area.  Use known perimeter same as of the triangle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%2A4=132 ALIGN=MIDDLE  ALT=\"s%2A4=132\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s=132%2F4 ALIGN=MIDDLE  ALT=\"s=132%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s=33 ALIGN=MIDDLE  ALT=\"s=33\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "AREA of the square, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=33%5E2=highlight%281089%2Acm%5E2%29 ALIGN=MIDDLE  ALT=\"33%5E2=highlight%281089%2Acm%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( "CIRCLE<BR>\n" );
document.write( "Need radius to find its area.  Use known perimeter same as of the triangle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar=132 ALIGN=MIDDLE  ALT=\"2pi%2Ar=132\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=132%2F%282pi%29 ALIGN=MIDDLE  ALT=\"r=132%2F%282pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=66%2Fpi ALIGN=MIDDLE  ALT=\"r=66%2Fpi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "AREA of the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2=pi%2A%2866%2Fpi%29%5E2=66%5E2%2Fpi ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2=pi%2A%2866%2Fpi%29%5E2=66%5E2%2Fpi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%284356%2Fpi%29cm%5E2%29 ALIGN=MIDDLE  ALT=\"highlight%28%284356%2Fpi%29cm%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If you want a computed approximation for this you might start with 1386.6.\r<BR>\n" );
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document.write( "You might find a ratio of area for Square to Circle any fair way you want.<BR>\n" );
document.write( "1089:1386.6 ?Square to Circle<BR>\n" );
document.write( "1386.6:1089  ?Circle to Square\r<BR>\n" );
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document.write( "If you were to divide BOTH of those numbers composing the ratio by 99, you will get something extremely near to  your expected 14:11.  The circle-to-square ratio.<BR>\n" );
document.write( "Other reportable ratios may also work well. </SPAN>\n" );
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