document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986381>Question 986381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I factor the following:\r<BR>\n" );
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document.write( "a^6-b^6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607146 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use cubes and squares<BR>\n" );
document.write( "this is a difference of cubes<BR>\n" );
document.write( "a^3-b^3=(a-b)(a^2+ab+b^2) coupled with a difference in squares as well (a^2-b^2)=(a+b)(a-b).  The only difference is the \"squares\" are a^3-b^3, and each one of those terms is factorable.<BR>\n" );
document.write( "Therefore, split this into a difference of squares problem, then factor each of those terms.<BR>\n" );
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document.write( "This is (a^3+b^3)(a^3-b^3)<BR>\n" );
document.write( "That is {(a+b)(a^2-ab+b^2)}X (a-b)(a^2+ab+b^2)} </SPAN>\n" );
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