document.write( "Question 986311: A study of the nicotine contents of a certain brand of cigarette shows that on the average of one cigarette contains 1.65 mg of nicotine with a standard deviation of 0.12 mg. According to chebyshev's theorem, between what values must the nicotine content be for at least 24/25 of all cigarettes of this brand? \n" ); document.write( "
Algebra.Com's Answer #607094 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A study of the nicotine contents of a certain brand of cigarette shows that on the average of one cigarette contains 1.65 mg of nicotine with a standard deviation of 0.12 mg. According to chebyshev's theorem, between what values must the nicotine content be for at least 24/25 of all cigarettes of this brand? \n" ); document.write( "-------- \n" ); document.write( "Note: 24/25 = 0.96 \n" ); document.write( "------ \n" ); document.write( "Solve for \"n\" \n" ); document.write( "(1+ (1/n)^2) >= 0.96 \n" ); document.write( "----- \n" ); document.write( "(1/n)^2 <= 0.04 \n" ); document.write( "----- \n" ); document.write( "(1/n) <= 0.2 \n" ); document.write( "n >= 1/0.2 = 5 \n" ); document.write( "Note: At least 96% of the data is within 5 standard deviations of the mean. \n" ); document.write( "---------- \n" ); document.write( "Ans: 1.65+-5*0.12 \n" ); document.write( "Lower limit: 1.05mg \n" ); document.write( "Upper limit: 2.25mg \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |