document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986280>Question 986280</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607074 by </B><A HREF=/tutors/aboutme.mpl?userid=abhimessi><B>abhimessi(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=abhimessi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> HEY THERE\r<BR>\n" );
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document.write( "GIVEN,PERIMETER OF THE FIELD=400m \r<BR>\n" );
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document.write( "LENGTH OF FIELD=26+b\r<BR>\n" );
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document.write( "PERIMETER FORMULA=2(L+B)\r<BR>\n" );
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document.write( "2(L+B)=400---->L+B=200  26+B+B=200(SINCE LENGTH IS 26+BREADTH)\r<BR>\n" );
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document.write( "26+2B=200 2B=174 OR B=87 M\r<BR>\n" );
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document.write( "LENGTH=26+87=113M </SPAN>\n" );
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