document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986270>Question 986270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a new rectangular playing field is 3 yards longer than quadruple the width. If the perimeter of the rectangular is 526 yards what are the dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607059 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be w\r<BR>\n" );
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document.write( "length I = 3+4w\r<BR>\n" );
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document.write( "perimeter = 2(w+(3+4w))=526\r<BR>\n" );
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document.write( "2w+6+8w=526\r<BR>\n" );
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document.write( "10w=526-6\r<BR>\n" );
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document.write( "10w=520\r<BR>\n" );
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document.write( "w=52\r<BR>\n" );
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document.write( "plug and find l\r<BR>\n" );
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document.write( "3+4*52<BR>\n" );
document.write( "3+208<BR>\n" );
document.write( "=211<BR>\n" );
document.write( " </SPAN>\n" );
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