document.write( "Question 986258: A coin collection has 18 coins consisting of quarters and dimes. There are two more dimes than the number of quarters. If the face value of collection is $3.00, how many quarters are in the collection? \n" ); document.write( "
Algebra.Com's Answer #607050 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "D=number of dimes; Q=number of quarters \n" ); document.write( ". \n" ); document.write( "D+Q=18 \n" ); document.write( "D=18-Q \n" ); document.write( ". \n" ); document.write( "$0.10D+$0.25Q=$3.00 \n" ); document.write( "$0.10(18-Q)+$0.25Q=$3.00 \n" ); document.write( "$1.80-$0.10Q+$0.25Q=$3.00 \n" ); document.write( "$0.15Q=$1.20 \n" ); document.write( "Q=8 \n" ); document.write( "ANSWER: There were 8 quarters. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( "D=18-Q=18-8=10 \n" ); document.write( "There were 10 dimes. \n" ); document.write( ". \n" ); document.write( "D=Q+2 \n" ); document.write( "10=8+2 \n" ); document.write( "10=10 \n" ); document.write( " \n" ); document.write( " |