document.write( "Question 986258: A coin collection has 18 coins consisting of quarters and dimes. There are two more dimes than the number of quarters. If the face value of collection is $3.00, how many quarters are in the collection? \n" ); document.write( "
Algebra.Com's Answer #607050 by macston(5194)\"\" \"About 
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\n" ); document.write( "D=number of dimes; Q=number of quarters
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\n" ); document.write( "D+Q=18
\n" ); document.write( "D=18-Q
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\n" ); document.write( "$0.10D+$0.25Q=$3.00
\n" ); document.write( "$0.10(18-Q)+$0.25Q=$3.00
\n" ); document.write( "$1.80-$0.10Q+$0.25Q=$3.00
\n" ); document.write( "$0.15Q=$1.20
\n" ); document.write( "Q=8
\n" ); document.write( "ANSWER: There were 8 quarters.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "D=18-Q=18-8=10
\n" ); document.write( "There were 10 dimes.
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\n" ); document.write( "D=Q+2
\n" ); document.write( "10=8+2
\n" ); document.write( "10=10
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