document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986264>Question 986264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I set up a system of equations to solve this:\r<BR>\n" );
document.write( "\n" );
document.write( "How many gallons of a 20% lemon and sugar solution must be mixed with how many gallons of a 40% lemon and sugar solution to make 10 gallons of a 28% lemon and sugar solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607048 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "T=amount of 20% solution; F=amount of 40% solution<BR>\n" );
document.write( ".<BR>\n" );
document.write( "T+F=10gallons<BR>\n" );
document.write( "T=10gal-F Use this to substitute for T.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "(0.20)T+(0.40)F=(0.28)10gal Substitute for T from above, solve for F. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );