document.write( "Question 986224: A square and an equilateral triangle have equal perimeters. The area of the triangle is 163 square centimeters. How long, in centimeters, is a diagonal of the square? Express your answer in simplest radical form. \r
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Algebra.Com's Answer #607030 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Triangle, side length s.
\n" ); document.write( "Altitude cuts triangle into two special 30 60 90 triangles.
\n" ); document.write( "A, the area of The equilateral triangle,
\n" ); document.write( "A/2, area of one of the special triangles.
\n" ); document.write( "a, altitude of the triangle.
\n" ); document.write( "\"a%5E2%2B%28s%2F2%29%5E2=s%5E2\"
\n" ); document.write( "\"a%5E2=s%5E2-%28s%2F2%29%5E2\"
\n" ); document.write( "\"a%5E2=s%5E2-%281%2F4%29s%5E2\"
\n" ); document.write( "\"a%5E2=%283%2F4%29s%5E2\"
\n" ); document.write( "\"a=%28s%2F2%29sqrt%283%29\"
\n" ); document.write( "\"A=2%28%281%2F2%29%28a%2F2%29%28s%2F2%29sqrt%283%29%29\", one-half base times height, twice
\n" ); document.write( "\"A=2a%2As%2Asqrt%283%29%2F%282%2A2%2A2%29\"
\n" ); document.write( "\"A=a%2As%2Asqrt%283%29%2F%282%2A2%29\"
\n" ); document.write( "substitute for a,
\n" ); document.write( "\"A=%28%28s%2F2%29sqrt%283%29%29%2As%2Asqrt%283%29%2F%282%2A2%29\"
\n" ); document.write( "\"A=%283%2As%5E2%29%2F8\"
\n" ); document.write( "Solve for s
\n" ); document.write( "\"s%5E2=A%2A8%2F3\"
\n" ); document.write( "\"s=2sqrt%282A%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "The SQUARE
\n" ); document.write( "Let x be the edge of square shape.
\n" ); document.write( "\"4x=3s\"
\n" ); document.write( "because perimeter of square is given as equal to perimeter of the equilateral triangle.
\n" ); document.write( "\"x=%283%2F4%29s\"
\n" ); document.write( "The diagonal of the square is d.
\n" ); document.write( "\"x%5E2%2Bx%5E2=d%5E2\"
\n" ); document.write( "\"d=sqrt%282x%5E2%29\"
\n" ); document.write( "\"d=x%2Asqrt%282%29\"
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\n" ); document.write( "Substitute for x to get better formula for d.
\n" ); document.write( "\"d=%283%2F4%29s%2Asqrt%282%29\"
\n" ); document.write( "Substitute for s to get yet a better formula for d.
\n" ); document.write( "\"d=%283%2F4%29%2A%282sqrt%282A%2F3%29%29%2Asqrt%282%29\"
\n" ); document.write( "\"d=%283%2F2%29sqrt%282%29sqrt%282A%2F3%29\"
\n" ); document.write( "\"d=%283%2F2%29sqrt%282%29sqrt%282%29sqrt%28A%2F3%29\"
\n" ); document.write( "\"d=3%2Asqrt%28A%2F3%29\"
\n" ); document.write( "Rationalize the expression, the denominator...
\n" ); document.write( "\"d=3%2Asqrt%283%29sqrt%28A%29%2F3\"
\n" ); document.write( "and remember, given A=163....
\n" ); document.write( "\"highlight%28d=sqrt%283%29sqrt%28163%29%29\"
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