document.write( "Question 986160: A store sells tents, sleeping bags, and camp stools. A customer buys a tent, 3 sleeping bags, and 5 camp stools for $213. The price of the tent is 7 times the cost of a camp stool. The cost of a sleeping bag is $26 more than the cost of a camp stool. Find the cost of each item. \n" ); document.write( "
Algebra.Com's Answer #606957 by algebrahouse.com(1659)\"\" \"About 
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t = price of tent
\n" ); document.write( "s = price of sleeping bag
\n" ); document.write( "c = cost of camp stool\r
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\n" ); document.write( "\n" ); document.write( "t = 7c {price of tent is 7 times cost of camp stool}
\n" ); document.write( "s = c + 26 {cost of sleeping bag is 26 more than cost of camp stool}
\n" ); document.write( "t + 3s + 5c = 213 {buys a tent 3 sleeping bags and 5 camp stools for $213}\r
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\n" ); document.write( "\n" ); document.write( "7c + 3(c + 26) + 5c = 213 {substituted 7c for t and (c + 26) in for s, into t + 3s + 5c = 213}
\n" ); document.write( "7c + 3c + 78 + 5c = 213 {used distrbutive property}
\n" ); document.write( "15c + 78 = 213 {combined like terms}
\n" ); document.write( "15c = 135 {subtracted 78 from each side}
\n" ); document.write( "c = 9 {divided each side by 15}\r
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\n" ); document.write( "\n" ); document.write( "t = 7c {first equation}
\n" ); document.write( "t = 7(9) {substituted 9, in for c, into first equation}
\n" ); document.write( "t = 63 {multiplied}\r
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\n" ); document.write( "\n" ); document.write( "s = c + 26 {second equation}
\n" ); document.write( "s = 9 + 26 {substituted 9, in for c, into second equation}
\n" ); document.write( "s = 35 {added}\r
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\n" ); document.write( "\n" ); document.write( "$9 = cost of camp stool
\n" ); document.write( "$63 = cost of tent
\n" ); document.write( "$35 = cost of sleeping bag
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