document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986146>Question 986146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Manufacturer A produces hammers that are normally distributed with a mean weight of 4.6 lb and a standard deviation of 0.8 lb. Manufacturer B produces hammers that are normally distributed with a mean weight of 6.3 lb and a standard deviation of 1.4 lb.\r<BR>\n" );
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document.write( "Which manufacturer is more likely to produce a hammer weighing exactly 5.2 lb? Explain. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #606924 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=606924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The coefficient of variation is the ratio of the sd to the mean.<BR>\n" );
document.write( "A: the coefficient is (0.8/4.6)=17.4%<BR>\n" );
document.write( "B: the coefficient is (1.4/6.3)=22.2%<BR>\n" );
document.write( "The desired weight is 3/4 of a sd above A and 0.786 sd below the mean in B.  But because B has a greater variability relative to the mean, and variability matters a great deal in quality control, manufacturer A would be more likely. </SPAN>\n" );
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