document.write( "Question 986150: Lina Chen invested $24,000, part at 8% and the rest at 7.2%. How much did she invest at each rate of her income from the 8% investment is two thirds that of the 7.2% investment? \n" ); document.write( "
Algebra.Com's Answer #606914 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=invested at 8% \n" ); document.write( "y=invested at 7.2% \n" ); document.write( "; \n" ); document.write( "x+y=24,000 \n" ); document.write( ".08x=(2/3)(.072)y \n" ); document.write( ".08x=0.048y \n" ); document.write( "x=0.6y \n" ); document.write( "substituting \n" ); document.write( "1.6y=24,000 \n" ); document.write( "y=$15,000 invested at 7.2%=$1080 per year \n" ); document.write( "x=$9000 invested at 8%=$720 per year. \n" ); document.write( "$720 is 2/3 of $1080. \n" ); document.write( " |