document.write( "Question 986150: Lina Chen invested $24,000, part at 8% and the rest at 7.2%. How much did she invest at each rate of her income from the 8% investment is two thirds that of the 7.2% investment? \n" ); document.write( "
Algebra.Com's Answer #606914 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
x=invested at 8%
\n" ); document.write( "y=invested at 7.2%
\n" ); document.write( ";
\n" ); document.write( "x+y=24,000
\n" ); document.write( ".08x=(2/3)(.072)y
\n" ); document.write( ".08x=0.048y
\n" ); document.write( "x=0.6y
\n" ); document.write( "substituting
\n" ); document.write( "1.6y=24,000
\n" ); document.write( "y=$15,000 invested at 7.2%=$1080 per year
\n" ); document.write( "x=$9000 invested at 8%=$720 per year.
\n" ); document.write( "$720 is 2/3 of $1080.
\n" ); document.write( "
\n" );