document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986085>Question 986085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Robert has 50 coins each 5 cents and 10 cents pieces which add up to 3.50 using an equation find how much of each type of coins there are? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #606857 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=606857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "N=number of 5 cent coins; D=number of 10 cent coins<BR>\n" );
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document.write( "N+D=50<BR>\n" );
document.write( "D=50-N Use this to substitute for D.<BR>\n" );
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document.write( "0.05N+0.10D=3.50 Substitute for D from above.<BR>\n" );
document.write( "0.05N+0.10(50-N)=3.50<BR>\n" );
document.write( "0.05N+5.00-0.10N=3.50<BR>\n" );
document.write( "-0.05N=-1.50<BR>\n" );
document.write( "N=30 ANSWER 1: There were thirty 5 cent coins.<BR>\n" );
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document.write( "D=50-N=50-30=20 ANSWER 2: There were twenty 10 cent coins.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
document.write( "0.05N+0.10D=3.50<BR>\n" );
document.write( "0.05(30)+0.10(20)=3.50<BR>\n" );
document.write( "1.50+2.00=3.50<BR>\n" );
document.write( "3.50=3.50\r<BR>\n" );
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document.write( " </SPAN>\n" );
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