document.write( "Question 986119: A 16' long car overtakes a 28' long truck. The truck is traveling at 30 mph. How fast must the car go to pass the truck in 4 seconds? \n" ); document.write( "
Algebra.Com's Answer #606849 by Boreal(15235)\"\" \"About 
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The front of the car has to be in front of the truck by at least 16 feet in 4 seconds. That is 44 feet in 4 seconds or 11 feet per second overtaking, in addition to the 44 feet per second the truck is moving.
\n" ); document.write( "(60 mph=88 feet/second, and that is useful to know).
\n" ); document.write( "55 feet per second is 5/8 of 60 mph, or 37.5 mph.
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