document.write( "Question 986006: Help to solve this equation:\r
\n" ); document.write( "\n" ); document.write( "〖log〗_10 x+ 〖log〗_10 2= 〖log〗_10 10-〖log〗_10 1
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Algebra.Com's Answer #606755 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
〖log〗_10 x+ 〖log〗_10 2= 〖log〗_10 10-〖log〗_10 1
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\n" ); document.write( "log(x) - log(2) = log(10) - log(1)
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\n" ); document.write( "log(x/2) = 1
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\n" ); document.write( "x/2 = 10
\n" ); document.write( "x = 20
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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