document.write( "Question 11856: If two numbers differ by 6, then what is the least possible value of their product? \n" ); document.write( "
Algebra.Com's Answer #6067 by rapaljer(4671)\"\" \"About 
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Let x = first number
\n" ); document.write( "x+6 = second number\r
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\n" ); document.write( "\n" ); document.write( "Let y = product of the numbers
\n" ); document.write( "y = x(x+6)
\n" ); document.write( "\"y+=+x%5E2+%2B+6x\"\r
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\n" ); document.write( "\n" ); document.write( "Graph the equation of this parabola, and find the lowest value of y, which is the vertex of the parabola. Algebraically, the vertex will always be at \"x+=+-b%2F%282a%29\" (where a=1, b=6 as in the quadratic formula!) so \"x+=+-6%2F2+=+-3\". Also halfway between the x intercepts, which would be at x=0 and x= -6. The minimum value of the product of the numbers would be
\n" ); document.write( "\"y+=+%28-3%29%5E2+%2B+6%28-3%29+=+9-18+=+-9\".\r
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\n" ); document.write( "\n" ); document.write( "\"graph+%28300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+%2B+6x%29\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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