document.write( "Question 985912: Jorge has a total of 50 coins, all of which are either dimes or nickels. The total value of the coins is $4.15. Find the number of each type of coin. \n" ); document.write( "

Algebra.Com's Answer #606693 by ikleyn(52830) $\"\"$ $\"About$

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\n" ); document.write( "Let n be the number of nickels Jorge has. \r
\n" ); document.write( "\n" ); document.write( "Then the number of dimes is 50-n.\r
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\n" ); document.write( "\n" ); document.write( "So, Jorge has 5*n cents in nickels and 10*(50-n) cents in dimes.\r
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\n" ); document.write( "\n" ); document.write( "In total, it is $4.15, which gives you an equation\r
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\n" ); document.write( "\n" ); document.write( "5*n + 10*(50-n) = 415.\r
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\n" ); document.write( "\n" ); document.write( "Solve it step by step:\r
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\n" ); document.write( "\n" ); document.write( "5n + 500 - 10n = 415,\r
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\n" ); document.write( "\n" ); document.write( "5n - 10n = 415 - 500,\r
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\n" ); document.write( "\n" ); document.write( "-5n = -85, \r
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\n" ); document.write( "\n" ); document.write( "n = $\"%28-85%29%2F%28-5%29\"$ = $\"85%2F5\"$ = 17.\r
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\n" ); document.write( "\n" ); document.write( "Thus Jorge has 17 nickels and 50-17 = 33 dimes. \r
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\n" ); document.write( "\n" ); document.write( "Check: 17*5 + 33*10 = 85 + 330 = 415. Correct!\r
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