document.write( "Question 985912: Jorge has a total of 50 coins, all of which are either dimes or nickels. The total value of the coins is $4.15. Find the number of each type of coin. \n" ); document.write( "
Algebra.Com's Answer #606692 by macston(5194)\"\" \"About 
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\n" ); document.write( "D=number of dimes; N=number of nickels
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\n" ); document.write( "D+N=50
\n" ); document.write( "D=50-N
\n" ); document.write( ".
\n" ); document.write( "$0.05N+$0.10D=$4.15
\n" ); document.write( "$0.05N+$0.10(50-N)=$4.15
\n" ); document.write( "$0.05N+$5.00-$0.10N=$4.15
\n" ); document.write( "-$0.05N=-$0.85
\n" ); document.write( "N=17 ANSWER 1: There were 17 nickels.
\n" ); document.write( "D=50-N=50-17=33 ANSWER 2: There were 33 dimes.
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\n" ); document.write( "CHECK:
\n" ); document.write( "$0.05N+$0.10D=$4.15
\n" ); document.write( "$0.05(17)+$0.10(33)=$4.15
\n" ); document.write( "$0.85+$3.30=$4.15
\n" ); document.write( "$4.15=$4.15
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