document.write( "Question 985840: I am trying to graph the function \"+g%28x%29=log3%28x-1%29+\" but i'm not sure if i'm supposed to place a horizontal or a vertical asymptote/where to place it, or what points to graph it at. Step by step would be helpful.\r
\n" ); document.write( "\n" ); document.write( "I am also supposed to give its domain and range using interval notation.
\n" ); document.write( "I think the domain is (1, ∞) but i'm not 100% confident
\n" ); document.write( "I think the range is (-∞,∞) but again, not sure. please correct me if i'm wrong.\r
\n" ); document.write( "\n" ); document.write( "Help would be extremely appreciated. Thank you so much, in advance!
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Algebra.Com's Answer #606610 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming the function is \"log%283%2C%28x-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "You have the correct domain and range. Nice work.\r
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\n" ); document.write( "\n" ); document.write( "To graph this function, you can plug in various values of x to get corresponding values of y. For example, if x = 2, then y = 0 giving the ordered pair (2,0). If x = 4, then y = 1 giving another point (4,1). Do this for other values of x.
\n" ); document.write( "Each (x,y) pair forms a point. Plot a bunch of points and draw a smooth curve connecting the points to complete the graph. \r
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\n" ); document.write( "\n" ); document.write( "You can use a graphing calculator like TI83 to confirm your graph. If you do not have a graphing calculator, you can use a free one like this one\r
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\n" ); document.write( "\n" ); document.write( "Note: you'll need to type in log(x-1)/log(3)\r
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\n" ); document.write( "\n" ); document.write( "Another note: This graph has NO horizontal asymptotes. It has exactly one vertical asymptote and it is x = 1.
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