document.write( "Question 985804: 3sqrt(2x2 - 7) = y/z make x the subject of the formulae \r
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Algebra.Com's Answer #606598 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"3sqrt%282x%5E2-7%29=+y%2Fz\"... make \"x\" the subject of the formula\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%282x%5E2-7%29=+%28y%2Fz%29%2F3\" \r
\n" ); document.write( "\n" ); document.write( "\"sqrt%282x%5E2-7%29=+%28y%2F3z%29\".........square both sides\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%282x%5E2-7%29%29%5E2=+%28y%2F3z%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-7=+%28y%2F3z%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2=+%28y%2F3z%29%5E2%2B7\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=+%28%28y%2F3z%29%5E2%2B7%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+sqrt%28%28%28y%2F3z%29%5E2%2B7%29%2F2%29\"\r
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