document.write( "Question 985802: solve algebra problem - the attendance at a ball fame was 400 people. students tickets cost $2 and adults tickets cost $3. if $1050 was collected in ticket sales how many if each type were sold. \n" ); document.write( "
Algebra.Com's Answer #606589 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A=number of adult tickets; S=number of student tickets \n" ); document.write( ". \n" ); document.write( "A+S=400 \n" ); document.write( "S=400-A \n" ); document.write( ". \n" ); document.write( "$2S+$3A=$1050 \n" ); document.write( "$2(400-A)+$3A=$1050 \n" ); document.write( "$800-$2A+$3A=$1050 \n" ); document.write( "$1A=$250 \n" ); document.write( "A=250 ANSWER 1: 250 adult tickets were sold. \n" ); document.write( "S=400-A=400-250=150 ANSWER 2: 150 student tickets were sold. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( "$2S+$3A=$1050 \n" ); document.write( "$2(150)+$3(250)=$1050 \n" ); document.write( "$300+$750+$1050 \n" ); document.write( "$1050=$1050 \n" ); document.write( " \n" ); document.write( " |