document.write( "Question 985802: solve algebra problem - the attendance at a ball fame was 400 people. students tickets cost $2 and adults tickets cost $3. if $1050 was collected in ticket sales how many if each type were sold. \n" ); document.write( "
Algebra.Com's Answer #606589 by macston(5194)\"\" \"About 
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\n" ); document.write( "A=number of adult tickets; S=number of student tickets
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\n" ); document.write( "A+S=400
\n" ); document.write( "S=400-A
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\n" ); document.write( "$2S+$3A=$1050
\n" ); document.write( "$2(400-A)+$3A=$1050
\n" ); document.write( "$800-$2A+$3A=$1050
\n" ); document.write( "$1A=$250
\n" ); document.write( "A=250 ANSWER 1: 250 adult tickets were sold.
\n" ); document.write( "S=400-A=400-250=150 ANSWER 2: 150 student tickets were sold.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "$2S+$3A=$1050
\n" ); document.write( "$2(150)+$3(250)=$1050
\n" ); document.write( "$300+$750+$1050
\n" ); document.write( "$1050=$1050
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