document.write( "Question 985582: If x^2 + y^2 = 2 and xy = -1, then x^3 + y^3 = ? \n" ); document.write( "
Algebra.Com's Answer #606532 by ikleyn(52814)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You have a system of two equations (non-linear) in two unknowns\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Express \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Introduce \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, x = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Correspondingly, y = -/+ 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, the pairs (x,y) = (1, -1) and (x,y) = (-1,1) are the solutions. There are no other solutions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It implies that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |