document.write( "Question 985673: Ken invests $2000 into two separate accounts. One earns 8% interest, the other earns 4.5% interest. If after one year, the total interest from the two accounts is $137.25, how much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #606511 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "E=amount at 8%; F=amount at 4.5% \n" ); document.write( ". \n" ); document.write( "E+F=$2000 \n" ); document.write( "F=$2000-E Use to substitute for F. \n" ); document.write( ". \n" ); document.write( "0.045F+0.08E=$137.25 Substitute for F from above. \n" ); document.write( "0.045($2000-E)+0.08E=$137.25 \n" ); document.write( "$90+0.045E+0.08E=$137.25 \n" ); document.write( "0.035E=$47.25 \n" ); document.write( "E=$1350 ANSWER 1: $1350 was deposited at 8%. \n" ); document.write( "F=$2000-E=$2000-$1350=$650 ANSWER 2: $650 was deposited at 4.5%. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( "0.045F+0.08E=$137.25 \n" ); document.write( "0.045($650)+0.08($1350)=$137.25 \n" ); document.write( "$29.25+$108=$137.25 \n" ); document.write( "$137.25=$137.25 \n" ); document.write( " \n" ); document.write( " |