document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=985647>Question 985647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Five years ago, a mother was twice as old as her son. In 6 years time, the sum of the ages will be 82. Find their present ages </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #606489 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=606489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = son's age 5 years ago<BR>\n" );
document.write( "2x = mother's age 5 years ago {mother was twice as old as son 5 years ago}\r<BR>\n" );
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document.write( "x + 5 = son's age now<BR>\n" );
document.write( "2x + 5 = mother's age now\r<BR>\n" );
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document.write( "x + 11 = son's age in 6 years<BR>\n" );
document.write( "2x + 11 = mother's age in 6 years\r<BR>\n" );
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document.write( "x + 11 + 2x + 11 = 82 {in 6 years time, the sum of the ages will be 82}<BR>\n" );
document.write( "3x + 22 = 82 {combined like terms}<BR>\n" );
document.write( "3x = 60 {subtracted 22 from each side}<BR>\n" );
document.write( "x = 20 {divided each side by 3}\r<BR>\n" );
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document.write( "x + 5 = 25 {substituted 20, in for x, into x + 5}<BR>\n" );
document.write( "2x + 5 = 45 {substituted 20, in for x, into 2x + 5}\r<BR>\n" );
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document.write( "son is 25 now<BR>\n" );
document.write( "mother is 45 now<BR>\n" );
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