document.write( "Question 985633: arccos(x)=arccos(x/2)\r
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Algebra.Com's Answer #606474 by ikleyn(52802) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let $\"alpha\"$ = $\"arccos%28x%29\"$ and $\"beta\"$ = $\"arccos%28x%2F2%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Then $\"cos%28alpha%29\"$ = $\"x\"$ and $\"cos%28beta%29\"$ = $\"x%2F2\"$ . \r
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\n" ); document.write( "\n" ); document.write( "Since $\"alpha\"$ = $\"beta\"$ by the condition, it implies that \r
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\n" ); document.write( "\n" ); document.write( " $\"x\"$ = $\"x%2F2\"$ .\r
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\n" ); document.write( "\n" ); document.write( "It is possible only if $\"x\"$ = $\"0\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Answer. x = 0. \r
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