document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84218>Question 84218</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0205459587/algebrahomeworkh>elementary statistics in social research</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Alight I kinda get the gist of what is going on with this problem but i'm having a hard time with the mean deviation which would mean I will have a hard time with the variance and standard deviation.\r<BR>\n" );
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document.write( "A focus group of 10 adults was chosen to evaluate the performance of a candidate during a presidential debate.  Each member of the group rated the overall perfomance on a scale of 1 (poor) to 10 (superior).  The ratings given the canidate were as follows:<BR>\n" );
document.write( "4 5 8 7 9 8 7 3 6 7 \r<BR>\n" );
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document.write( "Range 9-3=6 so the range is 6.\r<BR>\n" );
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document.write( "Mean deviation\r<BR>\n" );
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document.write( "I am not sure how to do this part at all...or the variance and standard devation part.  please can you help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60646 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Alight I kinda get the gist of what is going on with this problem but i'm having a hard time with the mean deviation which would mean I will have a hard time with the variance and standard deviation.<BR>\n" );
document.write( "A focus group of 10 adults was chosen to evaluate the performance of a candidate during a presidential debate. Each member of the group rated the overall perfomance on a scale of 1 (poor) to 10 (superior). The ratings given the canidate were as follows:<BR>\n" );
document.write( "4 5 8 7 9 8 7 3 6 7<BR>\n" );
document.write( "Range 9-3=6 so the range is 6.<BR>\n" );
document.write( "Mean deviation<BR>\n" );
document.write( "I am not sure how to do this part at all...or the variance and standard devation part. please can you help.<BR>\n" );
document.write( "TABULATE AND DO AS FOLLOWS.HOPE IT IS CLEAR.PLEASE COME BACK IF IN DOUBT			<BR>\n" );
document.write( "	x	X=x-M	X^2<BR>\n" );
document.write( "1	4	-2.4	5.76<BR>\n" );
document.write( "2	5	-1.4	1.96<BR>\n" );
document.write( "3	8	1.6	2.56<BR>\n" );
document.write( "4	7	0.6	0.36<BR>\n" );
document.write( "5	9	2.6	6.76<BR>\n" );
document.write( "6	8	1.6	2.56<BR>\n" );
document.write( "7	7	0.6	0.36<BR>\n" );
document.write( "8	3	-3.4	11.56<BR>\n" );
document.write( "9	6	-0.4	0.16<BR>\n" );
document.write( "10	7	0.6	0.36<BR>\n" );
document.write( "								<BR>\n" );
document.write( "SUM=S=	64	S.S.D. =	32.4	S.S.D=SUM OF SQUARES OF DEVIATIONS				<BR>\n" );
document.write( "N0.=N =	10	N0. = N = 	10					<BR>\n" );
document.write( "MEAN=M=	6.4	VARIANCE=V=	3.24	=MEAN OF SUM OF SQUARES OF DEVIATIONS				<BR>\n" );
document.write( "		S.D = SQRT.(V)	1.8	=ROOT OF MEAN OF SUM OF SQUARES OF DEVIATIONS				\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );