document.write( "Question 985594: Find all solutions of the equation in the interval [0,2π).\r
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document.write( "Write your answer in radians in terms of π.
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document.write( "If there is more than one solution, separate them with commas. \n" );
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Algebra.Com's Answer #606440 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find all solutions of the equation in the interval [0,2π).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "-------------- \n" ); document.write( "Sub 1 - sin^2 for cos^2, then it's a quadratic. \n" ); document.write( "--- \n" ); document.write( "4 - 4sin^2 = 5 - 4sin \n" ); document.write( "4sin^2 - 4sin + 1 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "======================== \n" ); document.write( "sin(x) = 1/2 \n" ); document.write( "x = pi/6, 5pi/6 \n" ); document.write( " |