document.write( "Question 84207: 1. An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have sold them together for $1535 with a profit of 10% on the first and 25% on the other artwork. Find the actual cost of each artwork. \n" ); document.write( "

Algebra.Com's Answer #60641 by PS(13) $\"\"$ $\"About$

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Assume first work costs x and second work costs y\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
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We'll use substitution. After moving 1.1*y to the right, we get:
\n" ); document.write( " $\"1.25%2Ax+=+1520+-+1.1%2Ay\"$ , or $\"x+=+1520%2F1.25+-+1.1%2Ay%2F1.25\"$ . Substitute that
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\n" ); document.write( " $\"1.1%2A%281520%2F1.25+-+1.1%2Ay%2F1.25%29+%2B+1.25%5Cy+=+1535\"$ and simplify: So, we know that y=700. Since $\"x+=+1520%2F1.25+-+1.1%2Ay%2F1.25\"$ , x=600.
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\n" ); document.write( " Answer: $\"system%28+x=600%2C+y=700+%29\"$ .
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\n" ); document.write( "\n" ); document.write( "So, the first artwork costs 600 and the second artwork costs 700 \n" ); document.write( "

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