document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=985492>Question 985492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to do systems of equations for algebra 2 I am stuck on the first problem which is 5x+4y=6<BR>\n" );
document.write( "                 -2x-3y= -1 can you help me out so far I have subtracted 5x - 2x and got 3x and I subtracted 3y from 4y and I have subtracted 6- -1 and got the equation 3x- 1y = 7 I think I cancel out the y value and divide 3x by 3 and 7 divided by 3 but I don't know I'm stuck please help me asap </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #606330 by </B><A HREF=/tutors/aboutme.mpl?userid=ThePhysicsMathGuru><B>ThePhysicsMathGuru(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ThePhysicsMathGuru><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=606330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  5x + 4y =  6    (1)<BR>\n" );
document.write( "-2x - 3y = -1    (2)\r<BR>\n" );
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document.write( "This set of simultaneous equations can be solved one of three different ways:<BR>\n" );
document.write( "1. Using determinates <BR>\n" );
document.write( "2. You can solve for x in equation (1) and then plug the value found for x into equation (2) and solve for y. You just have to remember,now you have the solution for y and you have to plug that value back into either equation to get the value for x.  <BR>\n" );
document.write( "3. Simply multiply both equations by a common value that will allow one of the variables to disappear. \r<BR>\n" );
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document.write( "I chose to use the latter. \r<BR>\n" );
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document.write( "If you multiply the first equation by 3 and the second by 4 you get the following\r<BR>\n" );
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document.write( "15x + 12Y = 18 <BR>\n" );
document.write( "-8x - 12y = -4<BR>\n" );
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document.write( "7x        = 14 <BR>\n" );
document.write( " x        = 2 <BR>\n" );
document.write( "What I did was simply add the two equations together. <BR>\n" );
document.write( "Now plug the value for x in either equation and solve. I chose to use the first one. \r<BR>\n" );
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document.write( "10 + 4y = 6<BR>\n" );
document.write( "4y = -4<BR>\n" );
document.write( " y = -1 <BR>\n" );
document.write( "So our solution is x = 2 and y = -1. One more step we need to verify that we did the computation correctly. Now plug the values for x and y back into each equation and you should get the numbers on the right hand side. \r<BR>\n" );
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document.write( " 2*5 + 4*(-1) = 6 <BR>\n" );
document.write( "-2*2 - 3*(-1) = -1 \r<BR>\n" );
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document.write( "Q.E.D We have not proven that the solution to the equation is x = 1 and y = -1 \r<BR>\n" );
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document.write( "Now plu </SPAN>\n" );
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