document.write( "Question 985497: The length of a rectangle is 5 more than the sides of square and the width of the rectangle is 5 less than the side of the square. If the area of the square is 45, what is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #606329 by macston(5194)\"\" \"About 
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\n" ); document.write( "a=side of square; L=length of rectangle=a+5; W=width of rectangle=a-5
\n" ); document.write( ".
\n" ); document.write( "Area of square=45
\n" ); document.write( "\"a%5E2=45\"
\n" ); document.write( "\"a=sqrt%2845%29\"
\n" ); document.write( ".
\n" ); document.write( "\"L=a%2B5=sqrt%2845%29%2B5\"
\n" ); document.write( "\"W=a-5=sqrt%2845%29-5\"
\n" ); document.write( ".
\n" ); document.write( "Area of rectangle=L*W
\n" ); document.write( "\"Area=%28sqrt%2845%29%2B5%29%28sqrt%2845%29-5%29\"=\"45-25=20\"
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