document.write( "Question 985492: I am trying to do systems of equations for algebra 2 I am stuck on the first problem which is 5x+4y=6
\n" ); document.write( " -2x-3y= -1 can you help me out so far I have subtracted 5x - 2x and got 3x and I subtracted 3y from 4y and I have subtracted 6- -1 and got the equation 3x- 1y = 7 I think I cancel out the y value and divide 3x by 3 and 7 divided by 3 but I don't know I'm stuck please help me asap \n" ); document.write( "

Algebra.Com's Answer #606327 by macston(5194) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "5x+4y=6 Multiply this by 2. This will help get 2 equations with equal x's.
\n" ); document.write( "10x+8y=12 Add this below.
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\n" ); document.write( "-2x-3y=-1 Multiply this by 5.
\n" ); document.write( "-10x-15y=-5 Add equation from above.
\n" ); document.write( "(-10x-15y)+(10x+8y)=-5+12
\n" ); document.write( "-7y=7
\n" ); document.write( "y=-1 Substitute this in one of the original equations.
\n" ); document.write( "5x+4y=6
\n" ); document.write( "5x+4(-1)=6
\n" ); document.write( "5x-4=6
\n" ); document.write( "5x=10
\n" ); document.write( "x=2
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\n" ); document.write( "CHECK (Use the other original equation):
\n" ); document.write( "-2x-3y=-1
\n" ); document.write( "-2(2)-3(-1)=-1
\n" ); document.write( "-4+3=-1
\n" ); document.write( "-1=-1
\n" ); document.write( ".
\n" ); document.write( "The answer is (2,-1)
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