document.write( "Question 985492: I am trying to do systems of equations for algebra 2 I am stuck on the first problem which is 5x+4y=6
\n" ); document.write( " -2x-3y= -1 can you help me out so far I have subtracted 5x - 2x and got 3x and I subtracted 3y from 4y and I have subtracted 6- -1 and got the equation 3x- 1y = 7 I think I cancel out the y value and divide 3x by 3 and 7 divided by 3 but I don't know I'm stuck please help me asap \n" ); document.write( "

Algebra.Com's Answer #606326 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
5x+4y = 6
\n" ); document.write( "-2x-3y= -1
\n" ); document.write( "--------------
\n" ); document.write( "To use elimination, you have to make the coefficients of either x or y match.
\n" ); document.write( "To eliminate x:
\n" ); document.write( " 5x+4y = 6 times 2 --> 10x + 8y = 12
\n" ); document.write( "-2x-3y= -1 times 5 -->-10x -15y = -5
\n" ); document.write( "------
\n" ); document.write( "10x + 8y = 12
\n" ); document.write( "-10x -15y = -5
\n" ); document.write( "------------------ Add
\n" ); document.write( "-7y = 7
\n" ); document.write( "y = -1
\n" ); document.write( "Sub for y in any equation to find x
\n" ); document.write( " 5x+4y = 6
\n" ); document.write( " 5x - 4 = 6
\n" ); document.write( "5x = 10
\n" ); document.write( "x = 2
\n" ); document.write( " \n" ); document.write( "

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