document.write( "Question 985474: Factors the polynomial P(x).then solve the equation P(x)=0.
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Algebra.Com's Answer #606315 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "5.\r\n" );
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document.write( "\"P%28x%29=x%5E4-x%5E3-19x%5E2%2B49x-30=0\"\r\n" );
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document.write( "Possible rational solutions are ±1, ±2, ±3, ±5, ±6, ±10, ±15, ±30\r\n" );
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document.write( "Try 2\r\n" );
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document.write( "1 | 1  -1 -19  49 -30\r\n" );
document.write( "  |     1   0 -19  30\r\n" );
document.write( "    1   0 -19  30   0\r\n" );
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document.write( "So we have factored P(x) as \r\n" );
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document.write( "\"P%28x%29=%28x-1%29%28x%5E3%2B0x%5E2-19x%2B30%29=0\"\r\n" );
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document.write( "Possible rational solutions to the second parenthetical expression\r\n" );
document.write( "set = 0 are ±1, ±2, ±3, ±5, ±6, ±10, ±15, ±30\r\n" );
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document.write( "Try 2\r\n" );
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document.write( "2 | 1   0 -19  30\r\n" );
document.write( "  |  2   4 -30\r\n" );
document.write( "    1   2 -15   0\r\n" );
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document.write( "So we have factored P(x) further as as\r\n" );
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document.write( "\"P%28x%29=%28x-1%29%28x-2%29%28x%5E2%2B2x-15%29=0%29\"\r\n" );
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document.write( "Now just factor the trinomial:\r\n" );
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document.write( "\"P%28x%29=%28x-1%29%28x-2%29%28x%2B5%29%28x-3%29=0%29\"\r\n" );
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document.write( "x-1=0;  x-2=0;  x+5=0;  x-3=0\r\n" );
document.write( "  x=1;    x=2     x=-5    x=3\r\n" );
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document.write( "Edwin
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