document.write( "Question 985460: Points A, B, and C lie on the circumference of a circle. AB is twice the radius of the circle. Find m(angle)ACB. \n" ); document.write( "
Algebra.Com's Answer #606266 by ikleyn(52796)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer. 90°.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since AB is twice the radius of the circle, AB is the diameter of the circle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The angle LACB is 90°, because it leans on the diameter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |