document.write( "Question 985457: parents set up a trust fund for their children last year. part of it is earning 7% simple interest per year while the rest of is is earning 6% simple interest per year. They placed $6000 in the trust fund. in one year the trust fund has earned $380. how much did they invest at each interest rate? \n" ); document.write( "
Algebra.Com's Answer #606261 by macston(5194)\"\" \"About 
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\n" ); document.write( "x=amount at 6%; y=amount at 7%
\n" ); document.write( "x+y=$6000
\n" ); document.write( "x=$6000-y
\n" ); document.write( ".
\n" ); document.write( "0.06x+0.07y=$380 Substitute for x from above.
\n" ); document.write( "0.06($6000-y)+0.07y=$380
\n" ); document.write( "$360-0.06y+0.07y=$380
\n" ); document.write( "0.01y=$20
\n" ); document.write( "y=$2000 ANSWER 1: $2000 was invested at 7%.
\n" ); document.write( ".
\n" ); document.write( "x=$6000-y=$6000-$2000=$4000 ANSWER 2: $4000 was invested at 6%.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.06x+0.07y=$380
\n" ); document.write( "0.06($4000)+0.07($2000)=$380
\n" ); document.write( "$240+$140=$380
\n" ); document.write( "$380=$380\r
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